D. 第一次循环,$\displaystyle n=1, s=\frac{2}{4 \times 1^{2}-1}$ ;第二次循环,$\displaystyle n=2, s=\frac{2}{4 \times 1^{2}-1}+\frac{2}{4 \times 2^{2}-1}$ ;直至 $\displaystyle n =1008, s=\frac{2}{4 \times 1^{2}-1}+\frac{2}{4 \times 2^{2}-1}+\cdots+\frac{2}{4 \times 1008^{2}-1}$ .结束循环,输出 $$ \begin{aligned} s & =\frac{2}{4 \times 1^{2}-1}+\frac{2}{4 \times 2^{2}-1}+\cdots+\frac{2}{4 \times 1008^{2}-1} \\ & =\frac{1}{2 \times 1-1}-\frac{1}{2 \times 1+1}+\frac{1}{2 \times 2-1}-\frac{1}{2 \times 2+1}+\cdots+\frac{1}{2 \times 1008-1}-\frac{1}{2 \times 1008+1} \\ & =\frac{1}{1}-\frac{1}{3}+\frac{1}{3}+\frac{1}{5}+\cdots+\frac{1}{2015}-\frac{1}{2017}=1-\frac{1}{2017}=\frac{2016}{2017} \end{aligned} $$