kaoyan2advanced 高等数学 第209题

教材习题

📝 题目

### 第209题

设 $z=f(2 x-y)+g(x, x y)$ ,其中 $f(t)$ 二阶可导,$g(u, v)$ 具有二阶连续偏导数,求 $\displaystyle \frac{\partial^{2} z}{\partial x \partial y}$ .

💡 答案解析

**答案**:$\displaystyle \frac{\partial^{2} z}{\partial x \partial y} = -2 f''(2x-y) + g_{uu} \cdot x + g_{uv} \cdot x^{2} + g_{v} + g_{vu} \cdot y + g_{vv} \cdot xy$ **解析**: 步骤1:令 $u=2x-y$,$v=x$,$w=xy$,则 $z=f(u)+g(v,w)$。$\displaystyle \frac{\partial z}{\partial x} = f'(u) \cdot 2 + g_v \cdot 1 + g_w \cdot y = 2f' + g_v + y g_w$。 步骤2:$\displaystyle \frac{\partial^{2} z}{\partial x \partial y} = \frac{\partial}{\partial y}(2f' + g_v + y g_w) = 2f'' \cdot (-1) + (g_{vv} \cdot 0 + g_{vw} \cdot x) + (1 \cdot g_w + y (g_{wv} \cdot 0 + g_{ww} \cdot x)) = -2f'' + x g_{vw} + g_w + xy g_{ww}$。注意 $g_{vw}=g_{uv}$,$g_{ww}=g_{vv}$,故答案为 $-2f''(2x-y) + x g_{uv}(x,xy) + g_v(x,xy) + xy g_{vv}(x,xy)$。 **难度**:★★★☆☆

📋 详细解题步骤

步骤 1/5
目标:引入中间变量,求一阶偏导
令 $u=2x-y$,$v=x$,$w=xy$,则 $z=f(u)+g(v,w)$。对 $x$ 求偏导: $$\frac{\partial z}{\partial x} = f'(u) \cdot \frac{\partial u}{\partial x} + g_v \cdot \frac{\partial v}{\partial x} + g_w \cdot \frac{\partial w}{\partial x} = f'(2x-y) \cdot 2 + g_v(x,xy) \cdot 1 + g_w(x,xy) \cdot y = 2f' + g_v + y g_w.$$
公式:$$\frac{\partial z}{\partial x} = f'(u) \cdot \frac{\partial u}{\partial x} + g_v \cdot \frac{\partial v}{\partial x} + g_w \cdot \frac{\partial w}{\partial x}$$
提示:注意g的偏导下标与变量对应
步骤 2/5
目标:对一阶偏导再求混合偏导
对 $\frac{\partial z}{\partial x}$ 关于 $y$ 求偏导: $$\frac{\partial^2 z}{\partial x \partial y} = \frac{\partial}{\partial y}(2f' + g_v + y g_w).$$
提示:注意混合偏导顺序和链式法则
步骤 3/5
目标:分别计算各项的偏导
第一项:$\frac{\partial}{\partial y}(2f') = 2f''(2x-y) \cdot \frac{\partial (2x-y)}{\partial y} = 2f'' \cdot (-1) = -2f''$。 第二项:$\frac{\partial}{\partial y}(g_v) = g_{vv} \cdot \frac{\partial v}{\partial y} + g_{vw} \cdot \frac{\partial w}{\partial y} = g_{vv} \cdot 0 + g_{vw} \cdot x = x g_{vw}$。 第三项:$\frac{\partial}{\partial y}(y g_w) = 1 \cdot g_w + y \cdot \frac{\partial g_w}{\partial y} = g_w + y \left( g_{wv} \cdot \frac{\partial v}{\partial y} + g_{ww} \cdot \frac{\partial w}{\partial y} \right) = g_w + y (g_{wv} \cdot 0 + g_{ww} \cdot x) = g_w + xy g_{ww}$。
公式:$$\frac{\partial}{\partial y}(g_v) = g_{vv} \cdot \frac{\partial v}{\partial y} + g_{vw} \cdot \frac{\partial w}{\partial y}$$
提示:注意链式法则中中间变量的顺序
步骤 4/5
目标:合并结果并化简
将各项相加: $$\frac{\partial^2 z}{\partial x \partial y} = -2f'' + x g_{vw} + g_w + xy g_{ww}.$$ 由于 $g$ 具有二阶连续偏导数,故 $g_{vw}=g_{uv}$,$g_{ww}=g_{vv}$,代入得: $$\frac{\partial^2 z}{\partial x \partial y} = -2f''(2x-y) + x g_{uv}(x,xy) + g_v(x,xy) + xy g_{vv}(x,xy).$$
公式:$$\frac{\partial^2 z}{\partial x \partial y} = -2f''(2x-y) + x g_{uv}(x,xy) + g_v(x,xy) + xy g_{vv}(x,xy)$$
提示:注意混合偏导顺序可交换条件
步骤 5/5
目标:最终答案
$$\boxed{\displaystyle \frac{\partial^{2} z}{\partial x \partial y} = -2 f''(2x-y) + x g_{uv}(x,xy) + g_v(x,xy) + xy g_{vv}(x,xy)}$$
公式:$$\frac{\partial^{2} z}{\partial x \partial y} = -2 f''(2x-y) + x g_{uv}(x,xy) + g_v(x,xy) + xy g_{vv}(x,xy)$$
提示:注意混合偏导次序和链式法则

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